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0=1x^2-190x+8625
We move all terms to the left:
0-(1x^2-190x+8625)=0
We add all the numbers together, and all the variables
-(1x^2-190x+8625)=0
We get rid of parentheses
-1x^2+190x-8625=0
a = -1; b = 190; c = -8625;
Δ = b2-4ac
Δ = 1902-4·(-1)·(-8625)
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1600}=40$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(190)-40}{2*-1}=\frac{-230}{-2} =+115 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(190)+40}{2*-1}=\frac{-150}{-2} =+75 $
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